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PHP : Function Reference : String Functions : strripos

strripos

Find position of last occurrence of a case-insensitive string in a string (PHP 5)
int strripos ( string haystack, string needle [, int offset] )

Example 2464. A simple strripos() example

<?php
$haystack
= 'ababcd';
$needle   = 'aB';

$pos      = strripos($haystack, $needle);

if (
$pos === false) {
   echo
"Sorry, we did not find ($needle) in ($haystack)";
} else {
   echo
"Congratulations!\n";
   echo
"We found the last ($needle) in ($haystack) at position ($pos)";
}
?>

The above example will output:

Congratulations!
  We found the last (aB) in (ababcd) at position (2)

Code Examples / Notes » strripos

aidan

This functionality is now implemented in the PEAR package PHP_Compat.
More information about using this function without upgrading your version of PHP can be found on the below link:
http://pear.php.net/package/PHP_Compat


electrofox

Sorry, I made that last post a bit prematurely.  One more thing wrong with the simple php4 version is that it breaks if the string is not found.  It should actually look like this:
<?php
if (function_exists('strripos') == false) {
   function strripos($haystack, $needle) {
$pos = strlen($haystack) - strpos(strrev($haystack), strrev($needle));
if ($pos == strlen($haystack)) { $pos = 0; }
       return $pos;
   }
}
?>
Note, we now check to see if the $needle was found, and if it isn't, we return 0.


yanik lupien

Simple way to implement this function in PHP 4
<?php
if (function_exists('strripos') == false) {
function strripos($haystack, $needle) {
return strlen($haystack) - strpos(strrev($haystack), $needle);
}
}
?>


peev dot alexander

I think you shouldn't underestimate the length of $needle in the search of THE FIRST POSITION of it's last occurrence in the string. I improved the posted function, with added support for offset. I think this is an exact copy of the real function:
<?php
if(!function_exists("strripos")){
function strripos($haystack, $needle, $offset=0) {
if($offset<0){
$temp_cut = strrev(  substr( $haystack, 0, abs($offset) )  );
}
else{
$temp_cut = strrev(  substr( $haystack, $offset )  );
}
$pos = strlen($haystack) - (strpos($temp_cut, strrev($needle)) + $offset + strlen($needle));
if ($pos == strlen($haystack)) { $pos = 0; }
return $pos;
}/* endfunction strripos*/
}/* endfunction exists strripos*/
?>


electrofox

Actually, the above, "Simple way to implement this function in PHP 4" by Yanik Lupien, should be:
<?php
if (function_exists('strripos') == false) {
   function strripos($haystack, $needle) {
       return strlen($haystack) - strpos(strrev($haystack), strrev($needle));
   }
}
?>
Note the reversal (<?php strrev($needle)?>) of the search string.  This was left out in Yanik's example, and without it, you'll simply get the length of the haystack, as the forward string will not likely be found in the reversed haystack.
Thus; if we reverse the haystack, any instance of the search string ($needle) therein will also be reversed, so we must reverse it to look for it. :)


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