Returns a month name
Code Examples / Notes » jdmonthname
YIQV, this should correct your issue with Adar being displayed as AdarI:
// assuming that $jewish_month is the Jewish month,
// and $jewish_year is the Jewish year,
// you can use this script to replace 'Adar I' with 'Adar' when it is not a leap year.
// this is because a Jewish leap year occurs every 3rd, 6th, 8th, 11th, 14th, 17th, and 19th year.
if( $jewish_month == "AdarI" &&
$jewish_year%19 != 0 &&
$jewish_year%19 != 3 &&
$jewish_year%19 != 6 &&
$jewish_year%19 != 8 &&
$jewish_year%19 != 11 &&
$jewish_year%19 != 14 &&
$jewish_year%19 != 17
$jewish_month = "Adar";
This is correct - remember that the Julian cal uses the correct latin - ie OCTober (octagon etc) is the 8th month. DECI (as in decimal etc etc) is the 10th month.
Slight error in the documentation above (though I believe the function works correctly). The Julian and Gregorian calendar options as noted above are reversed. Also, the documentation suggests that Julian and Gregorian have the same months, which is not the case. If you ask for the 10th month of the Julian calendar, you will get December instead of October (this produced some interesting results in a function I was working on...).
I am finding an inconsistency in the Jewish month Adar. The function always returns AdarI regardless of whether the year is a jewish leapyear. The month is known as Adar (not AdarI) in non-leap years. Also when using function jdtojewish with bool hebrew set to true it always returns (ADR) and not (ADR A) when it's a leap year. AdarII in Hebrew and English seems to work properly.