Returns the day of the week
Code Examples / Notes » jddayofweek
You can get todays day time and date using this code
echo date("d")." ";
echo date("m")." ";
echo date("Y")." ";
echo date("h:i:s A");
ECHO ' <br/>';
echo jddayofweek ( cal_to_jd(CAL_GREGORIAN, date("m"),date("d"), date("Y")) , 1 );
Maybe it is me since I am a newb but the above post on the use of mktime is wrong. You need to use GregorianToJD instead. I noticed this because when I used mktime, my day labels went backwards as I went forward through the month.
Be aware that date() and mktime() only work as long as you move within the UNIX era (1970 - 2038 / 0x0 - 0x7FFFFFFF in seconds). Outside that era those functions are only generating errors.
In other words: mktime(0, 0, 0, 12, 31, 1969) *DOES NOT* work (and so doesn't date() fed with with mktime()'s result from above). But cal_to_jd(CAL_GREGORIAN, 12, 11, 1969) *DOES WORK*.
And please note that the calendar-extension's functions arguments follow the US date order: month - day - year.